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show that cotxcot2x-cot2xcot3x-cot3xcotx=1
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Cot(A+B)=(CotACotB-1)/(CotA+CotB) Cot(x+2x)=(CotxCot2x-1)/(Cotx+Cot2x) Cot3x=(CotxCot2x-1)/(Cotx+Cot2x) Cot3xCotx+Cot3xCot2x=CotxCot2x-1 CotxCot2x-Cot3xCotx-Cot3xCot2x=1 |
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