lines 4x-7y+10=0 and and 7x+4y=15 are purpendicular to each other as slope of first line is 4/7 while slope of second line is -7/4 hence the triangle is a right angled triangle with these lines forming a right angle orthocentre is a point where the purpendiculars meet hence solving the two equations simultaneouslywe get the point (1,2)
Moderation Team
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