Let AB is a chord which makes 1200
Centre of the circle is O(3/2, -1/2)
C(x1,y1) is mid point of chord.
Now OC is perpendicular to AB
Sin(AngleOAC)=
[(x
1 - 3/2)
2 + (y
1+1/2)
2] / OA
Sin30=
[(x
1 - 3/2)
2 + (y
1+1/2)
2] / (3/2)
Required locus is:
(x - 3/2)2 + (y+1/2)2=(3/4)2
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Moderation Team
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