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Himanshu (9616)

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= 2pi (

x) / lamda

= phase diff. ................del. x is path diff.

2)normal shift

S = t (1 - 1/

).....................(

is not whole divided)

S_water = t/4

S_glass = t/3

3)wen a lens is cut into 2 = parts perpendicular to its principal axis , focal length gets doubled and power gets halved

4)wen a lens is cut into 2 = parts parallel to its P. Axis , no change in focal length or power takes place

5)Goggles donot hav any power coz R1 = R2 = R for them

so p = (

- 1) (1/R1 - 1/R2)

6)wen a lens is submerged in a denser medium its focal length inc and power dec.

7)wen a lens is submerged in water its focal length inc by 4 times and power dec. by 4 times

8)wen a lens is submerged in a medium of greater R.I then its nature reverses

9)Min. length of a plane mirror reqired to see full image of the object of ht. 'h' is h/2

10)* formula to calculate no. of images frmed b/w 2 mirrors is given by

n = 360/theta - 1

eg. if theta is 60.

then n = 5

Plz donot rate me here....m not pasting them to earn rates plzz....its to help u all...

if u wish to rate , then rate where i have posted this article...u have to find it , sorry...

cheers!!!!!!

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