Well A will go higher as for it the deceleration would be lower.

 

Let say the force of Drag (Air resistance) is - D

 

Now by Newtons second law F = ma

 

Hence,

Retardation of A = (D + m_Ag)/m_A = (D/m_A + g)

Retardation of B = (D + m_Bg)/m_B = (D/m_B + g)

So clearly retardation for B is greater than that for A and hence it will climb to a lesser hight