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Discussion Response Post to: trigo doubt

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19 Aug 2007 21:14:53 IST

Subject: Re:trigo doubt

aratrika (82)

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cos (A+B) =3/5

cos A cosB - sinA sinB= 3/5 (1`)

GIV: tanAtan B = 2

sin A/cosA * sin B /cosB = 2

or, sin A sin B = 2cosA cosB

or, cosA cos B = (sin A sin B)/2

putting the above value in eqn. (1), we get,

sinAsin B - 2 sinA sin B = 6/5

or, sinAsinB(1 -2) = 6/5

or, sinA sinB = - 6/5

so none of the options are correct .

PLZZZZZZ RATE ME , because i know i'm correct !!!!!

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