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santhosh in NUS (89)

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1. take conjugate
 
 (secA-tanA) (secA+tanA)/(secA-tanA)
 
=sec²A-tan²A/secA-tanA
 
=1/secA-tanA (since sec²A-tan²A =1)
 
it is the same for next also.
 
i hope iam correct.rate me if it is
 
useful .
 
cheers!!!!!!!

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