sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: work power and energy
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
karthik2007 (3399)

Blazing goIITian

Olaaa!! Perrrfect answer. 597  [804 rates]

karthik2007's Avatar

total posts: 2629    
offline Offline
Its quite simple. Now its given that it moves with constant acceleration.

That implies that it is under a constant force.

So F = constant.

Moreover, power = Fv (v = velocity at time t)

Also, v = u+at = at.
So, P = Fat.

But a = constant (acceleration is constant).

So, p = Kt=> P is proportional to the first power of t.

So A = 1.

Will nip in at times to solve problems :)
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya