a very good Question.......(an iit problem of 2001(or02) i suppose)
the exp. can be written as (x3m-1+x2m-1+xm-1)(2x3m+3x2m+6xm)1/m
U V
here if V is =t (say)
then Udx= 1/6mdt
thus integral= t (1+m)/m/6(1+m)......
this can be finalised by substuting for t......
rate me if you found my expln. satisfactory or do correct me if i were wrong.....................