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[Post New]8 Feb 2007 22:47:03 IST
    Subject: Re:Mechanics + electrostats
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yahiyafirdous (291)

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Olaaa!! Perrrfect answer. 47  [75 rates]
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ax=qE0/m
ay=0
 
x=(qE0/2m)t2
y=v0t
 
Eliminating t from above equations
 
y2=(2m/qE0)v02x
 
Find dy/dx and d2y/dx2  
 
  Radius of Curvature is given by
 [ 1 + (dy/dx)(dy/dx)]3/2 /[d2y/dx2]
 
Radius= 2x[1+(v02/2x)(m/qE0)]3/2       Answer
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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