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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Sep 2007 13:48:57 IST
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Initial conc =P/RT=0.8/(0.0821*293)=0.0333 miole per ltr
As temperature is 120 water will be in gaseous form so 1.5 moles of gas give one mole of water.
GFinal conc. = 20% of 0.0333+80%0.033333*1/1.5=0.02442mole/ltr
Final Pressure =0.02442*0.0821*393 = 0.787 atm
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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