IIT JEE , AIEEE Forum - Mathematics , Algebra

nadeemoidu

I dont know what 's the use of substituting u,v,w.
but u can do it like this
let x^logy=a
=> logy logx= log a ( taking log on both sides and using the formula log x^n=nlogx)
=> logx logy=log a
=> y^logx =a

therefore x ^logy= y^{log x} now substitute x^logy-logz as x^logy / x^logz ...
=x ^logy / z^logx
similarly doing like this to other terms, all will get cut and u get 1.

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