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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Sep 2007 13:46:34 IST
Accepted Answer [?]
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2)
cosx /(sinx+cosx)
now write numerator as [(cosx+sinx)+(cosx-sinx) ]/2
and break about the integral at "+".
now put sinx-cosx=t in 1st and sinx+cosx=t in 2nd integral.
and square both sides to get 2sinx.cosx =t^2-1 in 1st and 2sinx.cosx=1-t^2 in 2nd.
now substitute all values and get the answer.
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this reply: 10 points
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