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krishna.gopal (2327)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 371  bad job dude!! I dont approve of this answer! 2  [611 rates]

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Slight error in your analysis Anshuman. You missed the self energy term for the charge spread on the surface.

Initial energy = kQ1Q2/R1+kQ2^2/(2*R1)
final energy = kQ1Q2/R2+kQ2^2/(2*R2)

Now work done is equall to Efinal-Einitial

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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