IIT JEE , AIEEE Forum - Physics , Mechanics

swashata4iit

Well sinjan this is an easy one.

1. First find out the velocity of the car at t=10 sec using the formula

v = u + at [Here u = 0]

    Due to inertia this velocity will be the velocity of the stone.

2. When the stone is projected from the car then it only experiences an acc. due to gravity ie g. So no matter what be the time the acc. of the stone will be g.
    If after 10.1 sec from projection the stone reaches the ground then the wt of the stone will be balannced by the normal rxn provided by the ground on the stone and net acc will be 0, otherwise it will fall freely with an acc of g.
    I think the question is on finding the velocity of the stone after 10.1 sec of projection. If so then find out the vertical velocity of the stone after 10.1 sec(say z), and also check whether it will reach the ground or not. If it reaches the ground then the velocity will be 0. If not then the resultant velocity will be the resulant of the vectors v and z. Also find out the angle of the resultant velocity with using the formula of the vector...

    These are the concepts. If u want the soln. then nudge me!!!!!!!!!!!!!

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