Find the mechanical advantage of a machine ,which has a velocity ratio of 3:2,and efficiency75%
|
| Forum Index -> General Physics -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
The ratio, load/effort is called mechanical advantage of a machine. The mechanical advantage should be greater than one. If, in a machine, the ratio is less than one, it would be more accurate to call is mechanical disadvantage.
The ratio is called the velocity ratio of a machine. The two distances are moved in the same interval of time, so they are proportional to the velocities of the effort and load. P×d1 = W×d2 in a perfect machine. or where d1 and are d2 are the distances moved by effort P and load W respectively. Hence, in a perfect machine the mechanical advantage is equal to velocity ratio. In all machines some work is always wasted friction. The result of it is that the work done by the effort in a given time, called total work or work input (= p × d1) is always greater than the work done on the load (= W × d2) called useful work or work output. The difference of the latter from the former = lost work (Pd1-Wd2). The ratio is called efficiency of machine. It is also defined as the ratio In any actual machine the efficiency is always less than one but in a perfect or ideal machine in where there is no friction at all the efficiency is equal to unity. Or Mechanical advantage = Efficiency × velocity ratio i.e. M.A. =Velocity Ratio × η
.............................................. i think solution is clear now or numerical value might be 3/2 * .75== 3/2 * 3/4== 9/8== |
|||||||||||||
B Tech- IIIrd year Dep:- MEMS IIT Bombay Hostel-9 |
||||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||












