E-Store
A 0.5 gram of mono basic acid requires 16cm^3 of 0.1 mole dm^3 of NaOH for complete neutralization.w
|
| Forum Index -> Physical Chemistry -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
1000cm3 of 1 M NaOH is equivalent ot 40g NaOH Therefore, 16cm3 0.1M NaOH will be equivalent to 0.064g NaOH Now , 0.064g NaOH is required to neutralize 0.5g monobasic acid Therefore , 40g NaOH ( i.e. 1 mole) is equivalent to 312.5g of the acid. thus the relative mass of the acid should be 312.5 |
|||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||
Free Sign Up!
Preparing for IIT-JEE ?
Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor
@ INR 1,995/-
For Quick Info
|
|
|
|
|
| 35,229,755 Engineering Questions Attempted |
6,69,530 Visitors Monthly |
79 Engg. Exam Covered |
1702 Students Currently Online |
Connect with Us  |
 |
Vriti Communities
Privacy Policy © Vriti 2011