E-Store
Guys BReak ur head with these three ultimate problems...2nd one is very tough
|
| Forum Index -> Mechanics -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
Hello Vichu_487 , Q.3) As per the given problem , the initial velocity V1 of Car A is greater than velocoty V2 of Car B. Car A is Behind Car B at a distance "L" To Prevent the collision , atleast the velocity of Car A be reduced to V2. Let Car A Take time T ot reduce its speed from V1 to V2 In the same time car B moves distance say "x" Using the formula, V2 = U2 + 2aS We have : V22 = V12 - 2a(L+x) Where "a" is the retardation. Therefore , (L+x) = (V12 - V22)/2a ( Equation 1 ) Further using V = U + aT , We have : V2 = V1 - aT T = (V1-V2)/a .........(Equation 2 ) During this inteval the distance "x" travelled by the Car B is given by : x = V2T = V2(V1-V2)/a (Equation 3 ) Substituting the value of "x" from equation.(3) in Eq.(1) L + V2(V1-V2)/a = (V12-V22)/2a Solve the above part we will get : L = (V1-V2)2/2a To Prevent the collision , "L" should be greater than the above value : Therefore , L > (V1-V2)2/2a 2aL > (V1-V2)2 And hence the answer ... (V1-V2) <  (2aL)Hope you find it useful. plZ rate me if useful. Cheers!!!!!!!!!@@@!!!!!!!!!  |
|||||||||||||
Always available for help ! But Remember Don't hesitate to ask a good Question but Be damn serious for Questioning a weak one. <TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0"> <TR><TD> <DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE> [img]http://www.avatarsdb.com/avatars/fat_man_walk.gif[/img][url=http://www.avatarsdb.com/] [img]http://www.avatarsdb.com/avatars/angry_smile.gif[/img][/url][url=http://www.avatarsdb.com/] [img]http://www.avatarsdb.com/avatars/moon.gif[/img][/url] |
||||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||
Free Sign Up!
Preparing for IIT-JEE ?
Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor
@ INR 1,995/-
For Quick Info
|
|
|
|
|
| 35,229,755 Engineering Questions Attempted |
6,69,530 Visitors Monthly |
79 Engg. Exam Covered |
1362 Students Currently Online |
Connect with Us  |
 |
Vriti Communities
Privacy Policy © Vriti 2011