if a,b and c are in A.P then prove that,
(b + c), (c + a) and (a + b) are also in A.P
|
| Forum Index -> Algebra -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
it can be proven by using simple property of AP . that if any number is added , subtracted or multiplied by to every term of series .. new series will also be an AP . subtracting ( a+b+c) from each term ... so .. -(b+c) , - (a+c) , - (a+b) are in AP , multiplying with -1 , so (b + c), (c + a) and (a + b) are also in A.P |
|||||||||||||
future appears to be darker, if seen through the veil of past |
||||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||









