|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Oct 2007 23:01:22 IST
|
|
|
at equator g=g-w2r let at ehight H above south pole the acc. due to gravity is same g'=g(1-2h\r) g-w2r=g(1-2h\r) 1-w2r\2g=1-2h\r h=w2r2\2g solving u will get 10 km........
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|