Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: circles
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sowjanya gudipati (73)

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take the general eqn of circle with center (a,b) and radius r
(x-a)2+(y-b)2=r2
if lx+my+1=0 touches the circle then distance from center to the line is equal to radius
that is (la+mb+1)2=r2(l2+m2)
compare it with given condition which gives 2a=6,2bm=0,a2-r2=4,b2-r2=-5
which gives center to be (3,0)and radius as 5 units.
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