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 Discussion Response Post to:
shm
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Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Oct 2007 20:18:37 IST
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(b)
As the smaller block is on oscilating bigger block, it is in non inertial frame. So a pseudo force would act on it.
Force on bigger block at any instant = kx = Ma > a = kx/M
Thus an acceleration of kx/M acts on the smaller block in opposite direction.
When the block is above the acceleration is in downward direction (It is deaccelerating)
So the normal force = mg - ma = m (g - kx/M)
The reaction will be smallest at the extreme position in upward direction.
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