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[Post New]27 Oct 2007 21:17:33 IST
    Subject: Re:propertis of triangles
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venkat_tatolu (228)

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Olaaa!! Perrrfect answer. 30  [69 rates]
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Given equn, becomes   Sin2A+Sin2B+Sin2C=2  [by using sine rule]
 
                                2+2 CosA CosB CosC=2   [by transformations]
 
                                       CosA CosB CosC=0
 
So    either A or B or C = pi/2

Hence the triangle is right triangle.
 
***T.Venkat***
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