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Let the temperature of the junction C be some S.
Now, rate of entry of heat into C = rate of exit of heat from C (the rods are equal)
Since the rods are identical, K and A will be same.
Length of ac =  2 l
Therefore,
KA([ ] 2 T - S)/l = KA(S-T)/ 2l
We get 2T - 2 S = S-T
Which gives S = 3T/ 2 + 1
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Moderation Team
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