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Discussion Response Post to: Complex Number

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jagdish singh (1611)

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[img]http://latex.codecogs.com/gif.latex?\hspace{-16}$Here%20$\bf{\left|z+\frac{2}{z}\right|=2}$\\\\\\%20Now%20$\bf{\mid%20z%20\mid%20=\left|\left(z+\frac{2}{z}\right)-\frac{2}{z}\right|\leq%20\left|z+\frac{2}{z}\right|+\frac{2}{\mid%20z%20\mid}}$\\\\\\%20$\bf{\mid%20z%20\mid\leq%202+\frac{2}{\mid%20z%20\mid}}$\\\\\\%20$\bf{\mid%20z%20\mid^2-2\mid%20z%20\mid\leq%202}$\\\\\\%20$\bf{\left(\mid%20z%20\mid-1\right)^2\leq%20\left(\sqrt{3}\right)^2}$\\\\\\%20$\boxed{\boxed{\bf{\mid%20z%20\mid%20\leq%201+\sqrt{3}}}}$[/img]

Jagdish Singh.(Pantnagar)

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