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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Log problem
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spideyunlimited (3871)

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Olaaa!! Perrrfect answer. 649  [962 rates]

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arre see na
1/2 > (1/2)^2 > (1/2)^3
because
1/2 > 1/4 > 1/8
as the power of the fraction increases, the value decreases.
so as log 2 to the base 3 is a fraction greater than 1/2, it must be raised to a positive power so that it becomes 1/2.
like 1/3 ^2 = 1/9 where 1/3 is greater than 1/9.

after that i simply converted this statement into log equation.

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