IIT JEE , AIEEE Forum - Physics , Mechanics

karthik2007

You have not specified if the wheel is hollow or not.

Anyway, I will do it for both the cases. Now when the force is applied tangentially, it will produce a torque which will produce angular deceleration if the force is in the right direction.

Now, w = 100/60 rps = 5/3 rps.
angular displacement - 10 rev.

w1 (final angular velocity) = 0.

So, using w1²-w² = 2qa,

(here q = 10)

we get a = 5/36

We also know that torque = Ia = FR

If the wheel is hollow,I=mr²

putting this , we get F = 5/18 newton.

If wheel is not hollow, I = mr²/2,

which gives F = 5/36N

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