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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: linear momentum.............
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sowjanya_reddygudipati (73)

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Olaaa!! Perrrfect answer. 11  [20 rates]

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hey i am using the normal reaction offered by the floor on the chain which is equal to the force exerted by the chain on the floor
N=Nwt+Nthrust
Nwt=(m/l)xg
Nthrust=Vrelative(dm/dt)
Vrelative=u-v = v
dm/dt=(dm/dy)(dy/dt)=m/l(v)
Nthrust=v2(m/l)
v=(2gx)1/2
Nthrust=2gx(m/l)
N=(m/l)gx+2gx(m/l)=3(m/l)gx
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