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0.15 M CH3COOH and 0.2 M CH3COONa
means salt of weak acid and strong base.
And for weak acid and str. base, we have:
pOH = 7 - 1/2( pka + logc )
where c = molar conc. of the salt.
c = 0.1+0.15+0.2 [no. of moles remains constant]
pKa = 1.8*10^-5 [given]
pOH = 7 - 1/2 (1.8*10^-5 + 0.45)
= 7.173
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Moderation Team
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