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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Nov 2007 13:37:15 IST
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As we want the maximum pH, the ionic product=solubility product.
or [Mg2+][OH-]2 = 1.12x10-11
[Mg2+] = 0.1 (Given)
Solving for [OH-], we get [OH-] = 1.058x10-5.
Or pOH = -log(1.058x10-5)
or pOH = 4.97
pH = 14-pOH = 14-4.97 = 9.3
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Will nip in at times to solve problems :)
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this reply: 7 points
(with 1 
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Moderation Team
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