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no. of distinct 3 digits from {1,2,3,4,5,6} = 6C3
so no. of distinct equations =6C3 . 3!=120 (A,B,C are distinct )
and 6 other equations can be formed when A=B=C
but if we have to pick them without replacement...then answer should be 120 according to me....
if its with replacement then answer should be 126.....
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Moderation Team
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