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 Discussion Response Post to:
P&C
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Nov 2007 20:24:34 IST
Accepted Answer [?]
![[Up]](/templates/default/images/icon_up.gif "[Up]")
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A,B and C can have values 1 to 6 [ repetition is allowed]
so total no. of values possible = 6* 6* 6 = 216
now many cases will give the same equation . e.g. x2 + x +1=0 and
2x2 +2x + 2 =0 are same.
So let us find the total no. of such repetitions
let the equation be denoted by A-B-C
1-1-1 can be formed in 6 ways.
Here 5 are extra.
1-1-2 , 2-2-4 and 3-3-6 are same.
So there are 2 extra cases and it can be permuted in 3 ways each
total = 2x3 =6
Similarly 1-2-2 has 6 ways
1-1-3 has 3 ways
1-3-3 has 3 ways
1-2-3 . . . 6 ways
2-2-3 . . . 3 ways
2-3-3 . . . 3 ways
total of all extra equations = 5+6+3+6+3+6+3+3 = 35
Reqd. answer = 216 - 35 = 181
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this reply: 10 points
(with 2 
in 2 votes ) [?]
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Moderation Team
