Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Capacitors
Forum Index -> Electricity -> View Full Question Email  
Author Message
Vishwajeet Mishra (0)

New kid on the Block


Vishwajeet Mishra's Avatar

total posts: 1    
Offline
A charge of +2.0 x 10^-8 C is placed on the positive plate and a charge of -1.0 x 10^-8 C on the negative plate of a parallel plate capacitor of capacitance 1.2 x 10^-3 uF. Calculate the potential difference developed between the plates.
0 people liked this
 
Free Sign Up!
Sponsored Ads

Preparing for JEE?

Kickstart your preparation with new improved study material - Books & Online Test Series for JEE 2014/ 2015


@ INR 5,443/-

For Quick Info

Name

Mobile

E-mail

City

Class