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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Nov 2007 22:05:45 IST
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let I =  dx
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(sinx)^5 + (cosx)^5
I = dx
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(sinx +cosx)(1 - sinxcosx - (sinxcosx)^2)
I = (sinx + cosx)dx
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( 1 - 2sinxcosx) ( 1 - sinxcosx - (sinxcosx)^2)
now proceed by substituting sinx - cosx = t
squaring you will get
1 - 2sinxcosx=t^2
sinxcosx= 1/2*(1 - t^2)
substitute in the integral and proceed via the method of partial fractions ..............................
please do rate me if you are satisfied with my reply>>>>>>>>>
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