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 Discussion Response Post to:
circles
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Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Nov 2007 23:22:36 IST
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HIII...
well the figure is at the end of the qs...
figure mai u can see....4 circles passing thru the origin (i have to adjust it a lil bit..) and they cut off = chords of length a frm straight line y = +_ x
o is at the centre where all the circles meet
angle AOB = BOC = COD = DOA = pi/2
so AB , BC , CD , DA are the diametres of 4 circles..
angle XOA = pi/4 and OA = b...
C1A = bsin pi/4
OC1 = bcos pi/4
so we get co-ordinates of A = [b/root2 , b/root2]
similarly co-ordinates of
B = [ -b/root2 , b/root2]
C = [-b/root2 , -b/root2]
D = [b/root2 , -b/root2]
now equation of circle wid AD as diameter...
(x - (b/root2))(x - (b/root2)) + (y - (b/root2))(y + (b/root2)) = 0
= x2 + y2 - (root2)bx = 0
similarly...u can find other 3 equations...
and there must b +_ in ur answer...
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this reply: 20 points
(with 4 
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