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Let the initial distance between the two be d Let the source emit a pulse just after it starts moving So, velocity of this pulse is v ( = speed of sound in medium) It reaches the observer in time T1= d/ v
Also, the source is also moving. So, after timeperiod T, it emits a second pulse. At t=T, it has moved by s=0.T +1/2aT2=1/2aT2
So, time takento reach the observer for this pulse is = (Distance travelled to reach the Observer)/v = (d-1/2aT2)/v
So, t = Time diff in reaching of the 2 pulses =( T + (d-1/2aT2)/v) - d/v =T - aT2/2v So, apparent frequency = 1/ t = 2v/(2vT - aT2) Replace u = 1/T , Apparent frequency = 2vu2/(2vu - a)
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