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[Post New]15 Nov 2007 11:34:10 IST
    Subject: Re:even and odd function
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joyfrancis (1504)

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for odd function f(x)=-f(-x) i.e f(x)+f(-x)=0
log( (1 +x2)+x).+ log( (1 +x2)-x)
=log (1+x2-x2)
=log1=0
Hence the function is odd.
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