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When 2 plates of thickness d/5 are inserted, there are 3 capacitors formed.
With distance between each capacitor being d/5.
Let C' = Capacitor of 1 capacitor = kE0A/(d/5) = 5C
These 3 capacitors are in series. So, net capacitance is C'/3 = 5C/3
Check your answer please. It should be 5C/3 and not 3C/5
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Moderation Team
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