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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: HCV rotational
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rooney (894)

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Olaaa!! Perrrfect answer. 152  bad job dude!! I dont approve of this answer! 1  [221 rates]

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In the question, mass of rod is given to be 1 Kg.

So, I = 7/4 + 1x(1)^2 / 12
So, you get new value of Alpha.

As for tensions, let us consider the 5kg mass.
Its acceleration is = 0.5 m x Alpha = A

So, (weight of 5kg mass) - Tension = 5 x A
You get Tension from this equation. Same with the other mass.

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Rooney  

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