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solve this anyone
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solution A.M>=G.M a+b+c+d>=4 [abcd]^1/4 [abcd=1] a+b+c+d>=4 (4+a)+(4+b)+(4+c)+(4+d)/4>=[(4+a)(4+b)(4+c)(4+d)]^1/4 [16+a+b+c+d]^4 =(4+a)(4+b)(4+c)(4+d) and min. value of a+b+c+d=4 =[16+4/4]^4 =5^4 =625 ans. | |||||||||||||
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