IIT JEE , AIEEE Forum - Physics , Mechanics

karthik2007

Consider the first body. Let the height of the inclined plane be h.

Using conservation of energy, we get

1/2mv² = mgh.

which gives v² = 2gh - (1)

Consider the sphere. The sphere has both rotational and translational kinetic energy. Its moment of inertia about its COG is mr²/2.

Using conservation of energy again, we get:

mgh = 1/2mv'² + 1/4mv'² (using v=rw for pure rolling)

This gives 3v'² = 2v²

which gives v' =(

2/3)v.

Option C

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