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arg(x+iy)=tan inverse (y/x)
here y=(1+cos6
/5)
x=sin6
/5
so arg=tan inverse[(1+cos6
/5)/sin6
/5]
=tan inverse (2cos
26
/10/2sin6
/10.cos6
/10)
=tan inverse(cot6pi/10)
=tan inverse(tan{pi/2-6pi/10})
= tan inverse(tan{-pi/10})
=tan inverse(tan{pi+[-pi/10]})
= tan inverse(tan 9pi/10)
= 9pi/10
hence argument is 9pi/10.
Moderation Team
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