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[Post New]24 Nov 2007 15:14:57 IST
    Subject: Re:Progression- salute definitely
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spideyunlimited (3881)

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Olaaa!! Perrrfect answer. 651  [964 rates]
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nth term of the progression = n + 2 + [ 6 .2(n-1) ]
 
Sum of n terms = n2 + 2n  +   6.[1 ][ n ] 2(n-1)
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