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[Post New]16 Feb 2007 18:51:48 IST
    Subject: Re:Integration Problem
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raman_1290 (96)

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Olaaa!! Perrrfect answer. 16  [24 rates]
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I = (sinx.sin2x.sin3x)dx
 =  [(sinx)(2sinx.cosx)(3sinx - 4sin3x)]dx
 =  6sin3x.cosx.dx- 8sin5x.cosx.dx
Put sinx = t ; dt = cosx.dx
 =  6t3 -  8t5  = (3/2) t4 - (4/3) t6 + c
Hope its correct.
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