if m1 n m2 are slopes of tangents frm a point (1,4) on 16x2 - 25y2 = 400, then the point frm which the tangents drawn on hyperbola have slope
| m1 | n | m2 | n positive intercept on Y-axis is
(a) (-7, -4)
(b) (7, 4)
(c) (-4, -7)
(d) (4,7)
firstly pls tell how do u find a point frm where slopes of both tangents to the hyperbola are positive?? if ur considerin the 2 diff hyperbolas represented by the same eqn then its possible bt if its just one continuous hyperbola to right or left of the conjugate axis, then how do gt both tangents wit positive slopes??
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