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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Nov 2007 11:42:20 IST
Accepted Answer [?]
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oops sory!buzd up
now c
any point on ellipse will be (acosw, bsinw) (w is any angle)
normal at point w is
asecwx-bcosecwy=a^2-b^2
now compare
l/asecw=-m/bcosecw=-n/(a^2-b^2)
u get cosw=-an/l(a^2-b^2) n sinw=bn/m(a^2-b^2)
apply cos^2w+sin^2w=1
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