eqn of tangent is y=mx+/- rt(25m^2-16) putting (1, 4) here, we get two values of m as 1 and -4/3 so tangents with positive slopes will have m as 1 and 4/3 again put'em in y=mx+rt(25m^2-16) dis time take only +sign 4 intercept u'll get eqns of tangent as y=x+3 n y=4/3x+16/3 dere point of intersctin is (-7,-4)
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
Rahul Dey
Dept. of Electronics & Electrical
Communication Engineering,
IIT Kharagpur
Moderation Team
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