increase in pot energy=Gm1m2(1/0.5-1/1)=1.334*10^-8 since two particles r concerned, we'll take out the reduced mass u=m1m2/(m1+m2) =6.67 kg so 1/2 uv^2=U 1/2 * 6.67 * v^2=1.334*10^-8 v=6.33*10^-5m/s
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
Rahul Dey
Dept. of Electronics & Electrical
Communication Engineering,
IIT Kharagpur
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
120
