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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Nov 2007 22:57:54 IST
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eqn of projectile motion y=xtanw-gx^2/2u^2cos^2w (w is angle o pr)
putting g=10, u=21, w=60 dg
y=rt(3)x-20x^2/441 (i)
eqn of hill's slope is y=xtan30 or y=x/rt(3) (ii)
solving eqns (i) n (ii)
x=441/10rt(3) and y=441/30 coordinates of point where shell falls
dist frm hills bottom = rt(x^2+y^2)
=441/15
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