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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Dec 2007 10:50:27 IST
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See
(M+m)gsin37 = Ma FBD Of M
Now a psuedo force will be acting on m along the slope passing through the centre of mass m
Now Fbd of m relative to M would be
m( (M+m)gsin37 )cos37/M - umg = 0
So u = (M+m)sin37 )cos37/M
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